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The current flowing through the resistor in a series LCR a.c. circuit, is \( \boldsymbol{I}=\varepsilon / \boldsymbol{R} \) Now the inductor and capacitor are connected in parallel and joined in series with the resistor as shown in figure. The current in the circuit is now. (Symbols have their usual meaning)

1. equal to I
2. more than I
3. less than 1
4. zero

Correct answer: more than I

Solution

When the inductor and capacitor are connected in parallel, their susceptances add with opposite signs, so the branch can have a much smaller net impedance than either element alone. With less total opposition in series with the resistor, the circuit current becomes larger than \(\varepsilon/R\).

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