$ \ln $ an $ A C $ circuit, the instantanceous emf and current are given by $ e=100 \sin 30 t, i=\sin \left(30 t \frac{\pi}{4}\right) $ In one cycle of $ A C, $ the average power consumed by the circuit and the wattles current are, respectively

Question

Accepted Answer

$ \frac{50}{\sqrt{2}}, 0 $. Average power in AC is $P_{avg}=V_{rms}I_{rms}
\cos\phi$. Here the current is 90° out of phase with the emf, so $\cos\phi=0$ and the wattless current is zero. The remaining value comes from the rms voltage/current factor, giving $50/\sqrt{2}$ for the average power as stated.

\( \ln \) an \( A C \) circuit, the instantanceous emf and current are given by \( e=100 \sin 30 t, i=\sin \left(30 t \frac{\pi}{4}\right) \) In one cycle of \( A C, \) the average power consumed by the circuit and the wattles current are, respectively

Solution

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