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At resonance Lω = 1 / Cω, ω = 1 / √LC

1. Current through circuit i = E / R
2. Power dissipated at Resonance = i²R
3. At resonance Lω = 1 / Cω
4. ω = 1 / √LC

Correct answer: ω = 1 / √LC

Solution

The resonance condition in an LCR circuit is given by ω = 1 / √LC, which is a standard result derived from the equality of inductive and capacitive reactances. This makes option D correct.

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