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Condition for which the current is maximum in a series LCR circuit is:

1. ω = 1 / √LC ⇒ 1000 = 1 / √(10 × 10⁻⁶)
2. L = 100 mH
3. ω = 1 / √LC ⇒ 1000 = 1 / √(10 × 10⁻⁶)
4. L = 100 mH

Correct answer: ω = 1 / √LC ⇒ 1000 = 1 / √(10 × 10⁻⁶)

Solution

The current in a series LCR circuit is maximum at resonance, which occurs when the angular frequency ω equals 1/√LC. This is the condition for resonance, where the inductive and capacitive reactances cancel each other out.

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