In an A.C. circuit with voltage V and current I the power dissipated is:
dependent on the phase between V and I
1/√2 VI
1 VI
1/√1 VI
Correct answer: dependent on the phase between V and I
Solution
The power dissipated in an AC circuit depends on the phase difference between voltage (V) and current (I). The actual power is given by P = VIcos(ϕ), where ϕ is the phase angle between V and I.