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A 40 μF capacitor is connected to a 200 V, 50 Hz ac supply. The rms value of the current in the circuit is nearly:

1. 2.05 A
2. 2.5 A
3. 25.1 A
4. 1.7 A

Correct answer: 2.05 A

Solution

The capacitive reactance is given by Xc = 1 / (2πfC). Substituting f = 50 Hz and C = 40 μF, we get Xc ≈ 79.6 Ω. The rms current is then I = Vrms / Xc = 200 / 79.6 ≈ 2.05 A.

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