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If the input frequency of a full wave rectifier is \( 50 H z \) ac. Its output frequency is
- \( 50 H z \) pulsating dc
- \( 100 H z \) pulsating do
- \( 200 H z \) pulsating dc
- \( 500 H z \) pulsating dc
Correct answer: \( 100 H z \) pulsating do
Solution
In a full-wave rectifier, both the positive and negative half-cycles are converted into positive output pulses. That doubles the ripple frequency, so a 50 Hz input becomes 100 Hz at the output.
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