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A particle of mass \( m \) is made to move with uniform speed \( v \) along the perimeter of a regular hexagon. The magnitude of impulse applied at each corner is:

1. \( m v \)
2. \( m v \sqrt{3} \)
3. \( \frac{m v}{2} \)
4. \( \frac{m v}{\sqrt{3}} \)

Correct answer: \( m v \)

Solution

At each corner, the velocity direction changes by 120°, causing a change in momentum. Impulse equals this change, which is proportional to mv.

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