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For a common emitter amplifier, current gain is \( 60 . \) If the emitter current is \( 6.6 ~ m A \) the collector current is :
- \( 0.108 \mathrm{mA} \)
- 6.492 m \( A \)
- \( 1.1 \mathrm{m} \) А
- 3.3 \( m A \)
Correct answer: 6.492 m \( A \)
Solution
In a common-emitter transistor, current gain is typically \(\beta = I_C/I_B\). With \(\beta = 60\), the base current is \(I_B = I_C/60\), and since \(I_E = I_C + I_B\), the collector current is slightly less than the emitter current. That gives \(I_C = 6.492\,\text{mA}\).
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