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A 220 V, 50 Hz AC source is connected to an inductance of 0.2 H and a resistance of 20 \(\Omega\) in series. What is the current in the circuit?

1. 10 A
2. 5 A
3. 33.3 A
4. 3.33 A

Correct answer: 3.33 A

Solution

For a series RL circuit, \(X_L = 2\pi fL = 2\pi\times50\times0.2 \approx 62.8\,\Omega\). The impedance is \(Z = \sqrt{20^2 + 62.8^2} \approx 65.9\,\Omega\), so the current is \(I = V/Z = 220/65.9 \approx 3.33\) A.

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