If a current $I=I_0\sin\left(\omega t-\frac{\pi}{2}\right)$ flows in an AC circuit across which an AC potential $E=E_0\sin\omega t$ has been applied, then the power consumption $P$ in the circuit will be:

Question

Accepted Answer

P = 0. Here the current lags the voltage by $\pi/2$, so the phase difference is 90°. The average power in AC is $P_{avg}=V_{rms}I_{rms}\cos\phi$, and $\cos 90^\circ=0$, so power consumption is zero.

If a current \(I=I_0\sin\left(\omega t-\frac{\pi}{2}\right)\) flows in an AC circuit across which an AC potential \(E=E_0\sin\omega t\) has been applied, then the power consumption \(P\) in the circuit will be:

Solution

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