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The work done in adiabatic compression of 2 mole of an ideal monoatomic gas by constant external pressure of 2 atm starting from initia pressure of 1 atm and initial temperature of \( 300 K(R=2 \mathrm{cal} / \mathrm{mol}- \) degree celsius) is :

1. 360 cal
2. 720 call
3. 800 cal
4. 1000 call

Correct answer: 720 call

Solution

In an adiabatic process, q = 0, so the temperature rise comes entirely from work done on the gas. Using the adiabatic relation for a monoatomic gas and the given constant external pressure leads to a volume change that gives 720 cal of work.

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