Liquid benzene burns in oxygen according to: $ 2 C_{6} H_{6}+15 O_{2} \rightarrow 12 C O_{2}+6 H_{2} O $ If density of liquid benzene is $ 0.88 \mathrm{g} / \mathrm{cc} $ what volume of $ \boldsymbol{O}_{2} $ at $ \mathrm{STP} $ is needed to complete the combustion of 39 cc of liqu

Question

Liquid benzene burns in oxygen according to: $ 2 C_{6} H_{6}+15 O_{2} \rightarrow 12 C O_{2}+6 H_{2} O $ If density of liquid benzene is $ 0.88 \mathrm{g} / \mathrm{cc} $ what volume of $ \boldsymbol{O}_{2} $ at $ \mathrm{STP} $ is needed to complete the combustion of 39 cc of liquid benzene?

Accepted Answer

11.2 litre. The density lets you turn 39 cc of benzene into grams, then into moles. Using the reaction stoichiometry, each 2 moles of benzene need 15 moles of oxygen, and at STP 1 mole of gas occupies 22.4 L.

Solution

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