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For the reaction Zn(s) + Cu²⁺(aq) → Cu(s) + Zn²⁺(aq), where E° = +1.10V, the equilibrium relationship is given as E°cell = 0.0591/n log₁₀ Keq. If log₁₀ Keq is calculated to be 37.22, what is the value of Keq?

1. E° = +1.10V
2. E°cell = 0.0591/n log₁₀ Keq
3. log₁₀ Keq = 37.22
4. Keq = 1.66 × 10³⁷

Correct answer: Keq = 1.66 × 10³⁷

Solution

The equilibrium constant (Keq) is correctly calculated as 1.66 × 10³⁷ based on the given log₁₀ Keq value of 37.22. This matches the relationship between E°cell and Keq.

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