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What is the electric current required to deposit 0.972 g of chromium in three hours? (E.C.E. of chromium is 0.00018 g/c)

1. \( 0.50 A \)
2. 1A
3. zero
4. 2.5A

Correct answer: \( 0.50 A \)

Solution

For electrolysis, deposited mass equals E.C.E. times charge: m = ZQ. So Q = m/Z, and current is I = Q/t. Using the given values gives 0.50 A.

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