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The resistance of \( 1 \mathrm{N} \) solution of acetic acid is \( 250 \Omega \) when measured in a cell having a cell constant of \( 1.15 \mathrm{cm}^{-1} . \) The equivalent conduction (in oh \( m^{-1} c m^{2} e q u i v^{-1} \) ) of \( 1 N \) acetic acid is

1. 2.3
2. 4.6
3. 9.2
4. 18.4

Correct answer: 4.6

Solution

The solution’s conductivity is obtained from the cell constant divided by resistance. For a 1 N solution, equivalent conductance is then 1000 times conductivity divided by normality, giving 4.6 in the stated units.

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