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Calculate the potential difference (E) for the reaction Al → Al³⁺ + 3e⁻, given that for 1 mol of Al, n = 3, and for 4/3 mol of Al, n = 4. The equation ΔG = -nEF is applied, and the calculation involves: 827 × 1000 = 4 × E × 96500. Solve for E.

1. E = 827 × 1000 / 4 × 96500
2. E is equal to -2.14V
3. The value of n is 3 × 4/3 = 4
4. The equation used is ΔG = -nEF

Correct answer: E is equal to -2.14V

Solution

The correct answer is B) E = -2.14V because the calculation for E is correctly performed using the given formula and values.

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