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A compound weighing 0.35 g is analyzed, and 55 mL of nitrogen gas is collected. The room temperature is 300 K, the atmospheric pressure is 715 mm Hg, and the aqueous tension is 15 mm Hg. Determine the nitrogen percentage in the compound.

1. The nitrogen gas volume at NTP is calculated as (P–ρ) × V / t × 273 / 760.
2. (715–15) × 55 / 300 × 760 × 273 / 760 = 46.098 mL.
3. The percentage of nitrogen is given by 28 × volume of nitrogen at NTP × 100 / 22400 × mass of the compound.
4. Using the formula, 28 × 46.098 × 100 / 22400 × 0.35 = 16.46%.

Correct answer: Using the formula, 28 × 46.098 × 100 / 22400 × 0.35 = 16.46%.

Solution

The calculation involves correcting the nitrogen volume to NTP and then using the formula to find the percentage of nitrogen. The final step gives 16.46% as the correct answer.

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