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Calculate the percent composition of carbon in \( C_{6} H_{12} O_{6} \)

1. \( 50 \% \)
2. \( 40 \% \)
3. \( 35.3 \% \)
4. 22.1\%

Correct answer: \( 35.3 \% \)

Solution

The percent composition of an element is its mass in one mole of the compound divided by the compound’s molar mass, times 100. For glucose, carbon contributes 72 g out of a total 180 g, giving 35.3%.

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