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Which one of the followings has maximum number of atoms?
- 1 g of Mg(s) [Atomic mass of Mg = 24]
- 1 g of O2(g) [Atomic mass of O = 16]
- 1 g of Li(s) [Atomic mass of Li = 7]
- 1 g of Ag(s) [Atomic mass of Ag = 108]
Correct answer: 1 g of Li(s) [Atomic mass of Li = 7]
Solution
To find the maximum number of atoms, calculate the moles for each substance (mass/atomic mass) and multiply by Avogadro's number. Li has the smallest atomic mass, so 1 g of Li contains the most moles and hence the most atoms.
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