Exams › NEET › Chemistry

By analyzing the structures of three molecules, the number of lone pairs on the central nitrogen atom can be determined, which helps predict the bond angles. Arrange the bond angles in increasing order.

1. NO2⁻ < NO2 < NO2⁺
2. NO2 < NO2⁻ < NO2⁺
3. NO2⁺ < NO2 < NO2⁻
4. NO2 < NO2⁺ < NO2⁻

Correct answer: NO2⁻ < NO2 < NO2⁺

Solution

The bond angle depends on the number of lone pairs on the central atom. More lone pairs lead to greater repulsion, reducing the bond angle. The correct order of bond angles is determined by analyzing the electronic geometry of each species.

Related NEET Chemistry questions

• Which of the following have identical bond order? (I) \( \boldsymbol{C} \boldsymbol{N}^{-} \) (II) \( \boldsymbol{O}_{\mathbf{2}}^{-} \) \( (\|\|) N O^{+} \) \( (\mid V) C N^{+} \)
• What type of bond does \( M g \) form with \( C l ? \)
• Shape of \( C O_{2} \) is:
• The shape of \( s p^{3} d^{2} \) hybridized molecule with 2 lone pairs will be:
• The hybrid orbitals with \( 33.33 \% \) Scharacter are involved in the bonding of one of the crystalline allotropes of carbon. The allotrope is :
• In certain polar solvents \( \boldsymbol{P} \boldsymbol{C l}_{5} \) undergoes an ionisation reaction in which \( C l^{-} \) ion leaves one \( P C l_{5} \) molecule and attaches itself to another \( 2 P C l_{5} \rightleftharpoons P C l_{4}^{+}+P C l_{6}^{-} \) What are the changes in the geometrical shapes that occur in this ionisation?

⚔️ Practice NEET Chemistry free + battle 1v1 →