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When 9.85 g of BaCO3 decomposes into BaO and CO2, how much CO2 gas is released at STP?

1. 197 g of BaCO3 is involved in the reaction.
2. 197 g of BaCO3 produces 22.4 liters of CO2 at STP.
3. 1 g of BaCO3 generates 22.4/197 liters of CO2 at STP.
4. 9.85 g of BaCO3 produces CO2 equivalent to 22.4 × 9.85/197 = 1.12 liters at STP.

Correct answer: 9.85 g of BaCO3 produces CO2 equivalent to 22.4 × 9.85/197 = 1.12 liters at STP.

Solution

The decomposition of BaCO3 releases CO2, and the calculation for 9.85 g of BaCO3 releasing 1.12 L of CO2 at STP is correct based on stoichiometry and molar volume of gases.

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