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Determine the molarity of a sodium carbonate solution prepared by dissolving 25.3 grams of Na2CO3 in 106 milliliters of solution.

1. 0.955 mol/L
2. 1.91 mol/L
3. 0.955 mol/L
4. 2 mol/L

Correct answer: 0.955 mol/L

Solution

To calculate molarity, use the formula M = moles of solute / volume of solution in liters. Moles of Na2CO3 = 25.3 g / 106 g/mol = 0.2385 mol. Volume = 106 mL = 0.106 L. M = 0.2385 / 0.106 = 0.955 M.

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