Cu2+ + 2e− → Cu; ΔG° = −nFE°. ΔG° = −2×F×0.337 = −0.674F. Cu+ → Cu2+ + e−; ΔG° = −nFE°. ΔG° = −1×F×0.153 = 0.153F. On adding eqn (i) & (ii), Cu+ → Cu; ΔG° = −0.521F = −nFE°. Here n = 1, E° = +0.52V.

Question

Accepted Answer

Cu+ → Cu. The question involves combining the given ΔG° values to derive the standard electrode potential (E°) for the reaction Cu+ → Cu. The correct reaction corresponding to the derived E° value of +0.52 V is Cu+ → Cu.

Cu2+ + 2e− → Cu; ΔG° = −nFE°. ΔG° = −2×F×0.337 = −0.674F. Cu+ → Cu2+ + e−; ΔG° = −nFE°. ΔG° = −1×F×0.153 = 0.153F. On adding eqn (i) & (ii), Cu+ → Cu; ΔG° = −0.521F = −nFE°. Here n = 1, E° = +0.52V.

Solution

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