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Cu + 2Ag+ → Cu2+ + 2Ag(s). Here, n = 2, E°cell = +0.46 V. ΔG° = −nFE° = −2×0.46×96500/1000 kJ = −89 kJ.

1. Cu + 2Ag+ → Cu2+ + 2Ag(s)
2. Cu2+ + 2Ag → Cu + 2Ag+
3. Cu + Ag+ → Cu+ + Ag
4. Cu2+ + Ag → Cu + Ag+

Correct answer: Cu + 2Ag+ → Cu2+ + 2Ag(s)

Solution

The given reaction Cu + 2Ag+ → Cu2+ + 2Ag(s) matches the data provided, including n = 2 and E°cell = +0.46 V, which leads to ΔG° = −89 kJ. This confirms option A is correct.

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