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During the electrolysis of dil. sulphuric acid using Pt electrodes, the following reaction occurs. At cathode: 4H⁺(aq) + 4e⁻ → 2H₂(g). At anode: 2H₂O(l) → O₂(g) + 4H⁺(aq) + 4e⁻.

1. At cathode: 4H⁺(aq) + 4e⁻ → 2H₂(g)
2. At anode: 2H₂O(l) → O₂(g) + 4H⁺(aq) + 4e⁻
3. Electrolysis of dil. sulphuric acid
4. Pt electrodes are used

Correct answer: At cathode: 4H⁺(aq) + 4e⁻ → 2H₂(g)

Solution

The reaction at the cathode is correctly represented as 4H⁺(aq) + 4e⁻ → 2H₂(g), which is a reduction process where hydrogen ions gain electrons to form hydrogen gas.

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