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Given current (i) = 0.5 A; Time (t) = 100 minutes × 60 = 6000 sec; Equivalent weight of silver nitrate (E) = 108. According to Faraday's first law of electrolysis, W = Eit / 96500 = 108 × 0.5 × 6000 / 96500 = 3.3575 g.

1. W = 3.3575 g
2. E = 108
3. i = 0.5 A
4. t = 6000 sec

Correct answer: W = 3.3575 g

Solution

The question asks for the weight (W) of silver deposited, which is calculated using Faraday's first law of electrolysis. The correct calculation gives W = 3.3575 g, making option A correct.

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