Given molarity = 0.01 M, Resistance = 40 ohm; Cell constant = 1 A = 0.4 cm⁻¹, Specific conductivity (κ) = cell constant / resistance = 0.4 / 40 = 0.01 ohm⁻¹ cm⁻¹, Molar conductance (Λm) = 1000κ / Molarity = 1000 × 0.01 / 0.01 = 10³ ohm⁻¹ cm² mol⁻¹.

Question

Accepted Answer

Molar conductance = 10³ ohm⁻¹ cm² mol⁻¹. The calculation for molar conductance (Λm) is correct: Λm = (1000 × κ) / Molarity = (1000 × 0.01) / 0.01 = 10³ ohm⁻¹ cm² mol⁻¹. Thus, option C is correct.

Given molarity = 0.01 M, Resistance = 40 ohm; Cell constant = 1 A = 0.4 cm⁻¹, Specific conductivity (κ) = cell constant / resistance = 0.4 / 40 = 0.01 ohm⁻¹ cm⁻¹, Molar conductance (Λm) = 1000κ / Molarity = 1000 × 0.01 / 0.01 = 10³ ohm⁻¹ cm² mol⁻¹.

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