Exams › NEET › Chemistry

If E°Fe2+/Fe = –0.441 V and E°Fe3+/Fe2+ = +0.771 V, the standard EMF of the reaction Fe + 2Fe3+ → 3Fe2+ will be

1. 1.653 V
2. 1.212 V
3. 0.111 V
4. 0.330 V

Correct answer: 1.212 V

Solution

The standard EMF of the reaction is calculated using the formula E°cell = E°cathode - E°anode. Here, Fe3+/Fe2+ acts as the cathode (+0.771 V) and Fe2+/Fe as the anode (-0.441 V). Substituting, E°cell = 0.771 - (-0.441) = 1.212 V.

Related NEET Chemistry questions

• Assertion: When an electric current is passed through the copper sulphate electrolyte, the impure copper anode gradually dissolve and pure copper is deposited on the cathode. Reason: Pure metals are deposited in electroplating techniques.
• What is the electric current required to deposit 0.972 g of chromium in three hours? (E.C.E. of chromium is 0.00018 g/c)
• Which of the following statement (s) differentiate between electrochemical cell and electrolytic cell? This question has multiple correct options
• Among the following, the couple with most positive reduction potential is :
• The resistance of \( 1 \mathrm{N} \) solution of acetic acid is \( 250 \Omega \) when measured in a cell having a cell constant of \( 1.15 \mathrm{cm}^{-1} . \) The equivalent conduction (in oh \( m^{-1} c m^{2} e q u i v^{-1} \) ) of \( 1 N \) acetic acid is
• If \( 9 g m H_{2} O \) is electrolysed completely with the current of \( 50 \% \) efficiency then :

⚔️ Practice NEET Chemistry free + battle 1v1 →