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Given: Cu2+ + 2e- → Cu, E° = 0.337 V Cu2+ + e- → Cu+, E° = 0.153 V Electrode potential, E° for the reaction, Cu+ + e- → Cu, will be:
- 0.90 V
- 0.30 V
- 0.38 V
- 0.52 V
Correct answer: 0.38 V
Solution
The electrode potential for Cu+ + e- → Cu can be calculated using the relationship E°(Cu2+ → Cu) = E°(Cu2+ → Cu+) + E°(Cu+ → Cu). Substituting the given values, 0.337 V = 0.153 V + E°(Cu+ → Cu), solving gives E° = 0.38 V.
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