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Consider the following relations for emf of a electrochemical cell: (i) emf of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) emf of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii) emf of cell = (Reduction potential of anode) + (Reduction potential of cathode) (iv) emf of cell = (Oxidation potential of anode) - (Oxidation potential of cathode) Which of the above relations are correct?

1. (i) and (iv)
2. (iii) and (ii)
3. (i) and (ii)
4. (iii) and (iv)

Correct answer: (iii) and (ii)

Solution

The correct relations for the emf of a cell are (ii) and (iii). This is because the emf of a cell is calculated as the sum of the oxidation potential of the anode and the reduction potential of the cathode, or equivalently, the sum of the reduction potentials of both electrodes (with the anode's reduction potential being negative).

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