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The equivalent conductance of M/32 solution of a weak monobasic acid is 8.0 mho cm² and at infinite dilution is 400 mho cm². The dissociation constant of this acid is:

1. 1.25 × 10⁻⁶
2. 6.25 × 10⁻⁴
3. 1.25 × 10⁻⁴
4. 1.25 × 10⁻⁵

Correct answer: 1.25 × 10⁻⁴

Solution

The degree of dissociation (α) is calculated as the ratio of the equivalent conductance at the given concentration to that at infinite dilution: α = 8.0 / 400 = 0.02. Using the formula for the dissociation constant, Ka = (Cα²), where C = 1/32 = 0.03125 M, we get Ka = 0.03125 × (0.02)² = 1.25 × 10⁻⁴.

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