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Limiting molar conductivity of NH4OH (i.e., Λ°m(NH4OH)) is equal to:

1. (a) Λ°m(NH4Cl) + Λ°m(NaOH) − Λ°m(NaCl)
2. (b) Λ°m(NaOH) + Λ°m(NH4Cl) − Λ°m(NH4Cl)
3. (c) Λ°m(NaOH) + Λ°m(NH4Cl) − Λ°m(HCl)
4. (d) Λ°m(NH4Cl) + Λ°m(NaOH) − Λ°m(NaCl)

Correct answer: (a) Λ°m(NH4Cl) + Λ°m(NaOH) − Λ°m(NaCl)

Solution

The limiting molar conductivity of NH4OH can be calculated using Kohlrausch's law of independent migration of ions. It is given by the sum of the limiting molar conductivities of NH4Cl and NaOH, minus that of NaCl, as the contributions of common ions cancel out.

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