Exams › NEET › Chemistry

What is the mole fraction of the solute in a 1.00 m aqueous solution?

1. 0.177
2. 1.770
3. 0.0354
4. 0.0177

Correct answer: 0.177

Solution

In a 1.00 m aqueous solution, 1 mole of solute is dissolved in 1 kg (1000 g) of water. The mole fraction is calculated as moles of solute divided by total moles (solute + solvent). Assuming water's molar mass is 18 g/mol, moles of water = 1000/18 ≈ 55.56. Mole fraction = 1 / (1 + 55.56) ≈ 0.0177.

Related NEET Chemistry questions

• Which of the following statements is/are correct? This question has multiple correct options
• Calculate the \( \% \) composition of Carbon in \( C O_{2} . \) Molar mass is 44.01
• Which of the following rules regarding the significant figures and calculations involving them is not correct?
• \( 16.8 \mathrm{g} \) of metal carbonate on thermal decomposition gave 8 g of metallic oxide and \( 8.8 \mathrm{g} \) of carbon dioxide. They follow:
• Calculate the percent composition of carbon in \( C_{6} H_{12} O_{6} \)
• Which one of the followings has maximum number of atoms?

⚔️ Practice NEET Chemistry free + battle 1v1 →