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Angle increases progressively sp3 (109°28'), sp2 (120°), sp (180°). Which of the following compounds has sp hybridization?

1. CH3-CH=CH-CH2
2. CH3-C≡C-CH3
3. CH3-CH=CH-C=CH2
4. CH3-CH2-CH=CH-CH3

Correct answer: CH3-C≡C-CH3

Solution

In CH3-C≡C-CH3, the carbon atoms involved in the triple bond exhibit sp hybridization due to the linear geometry and 180° bond angle characteristic of sp hybridized orbitals.

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