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Which of the following statements is correct for a reversible process in a state of equilibrium?

1. ΔG = 2.30 RT log K
2. ΔG = −2.30 RT log K
3. ΔG° = 2.30 RT log K
4. ΔG° = −2.30 RT log K

Correct answer: ΔG° = −2.30 RT log K

Solution

For a reversible process at equilibrium, the standard Gibbs free energy change (ΔG°) is related to the equilibrium constant (K) by the equation ΔG° = −2.30 RT log K. This is a fundamental thermodynamic relationship.

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