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During isothermal expansion of ideal gas, ΔT = 0. Now ΔH = ΔE + PΔV ΔH = ΔE + Δ(nRT) ΔH = ΔE + Δ(nRT) Thus, if ΔT = 0, ΔH = ΔE i.e., remain unaffected.

1. (a) ΔH = ΔE
2. (b) ΔH = ΔE + ΔnRT
3. (c) ΔH = ΔE − ΔnRT
4. (d) ΔH = ΔE + ΔnRT

Correct answer: (a) ΔH = ΔE

Solution

In an isothermal process, ΔT = 0, which means there is no change in temperature. Since enthalpy (ΔH) depends on temperature for an ideal gas, ΔH = ΔE. Thus, the correct answer is (a).

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