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Given ΔH = 30 kJ mol⁻1, T = 273 + 27 = 300 K, ΔS = ΔH/T = 3 × 10⁴/300 J mol⁻1 = 100 J mol⁻1 K⁻1

1. ΔS = ΔH/T
2. ΔS = ΔH/T × 273
3. ΔS = ΔH/T × 3 × 10⁴
4. ΔS = ΔH/T × 100 J mol⁻1 K⁻1

Correct answer: ΔS = ΔH/T

Solution

The correct formula for entropy change is ΔS = ΔH/T, as per thermodynamic principles. The other options introduce unnecessary or incorrect factors.

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