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In 2H(g) → H2(g), no. of moles decreases, therefore entropy decreases.
- ΔS = ΔH/T
- ΔS = ΔH/T × 273
- ΔS = ΔH/T × 1.435 × 10³
- ΔS = ΔH/T × 5.260 cal mol⁻K
Correct answer: ΔS = ΔH/T
Solution
Entropy change (ΔS) is proportional to the enthalpy change (ΔH) divided by the absolute temperature (T), as per thermodynamic principles.
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