Exams › NEET › Chemistry

2H2O(l) → 2H2O(g) + O2(g) ΔH = ? ΔH = [2 × ΔHf of H2O(l)] + (ΔHf of O2) = −(2 × ΔHf of H2O(l))

1. (a) [−572 + 376] = −196 kJ/mole
2. (b) [−572 + 376] = −196 kJ/mole
3. (c) [−572 + 376] = −196 kJ/mole
4. (d) [−572 + 376] = −196 kJ/mole

Correct answer: (a) [−572 + 376] = −196 kJ/mole

Solution

The question contains identical options, which is likely an error. Based on the calculation provided, the correct ΔH value is -196 kJ/mole. The first option is chosen arbitrarily as all options are the same.

Related NEET Chemistry questions

• An ideal gas is compressed in a closed container its U?
• Internal energy does not include
• Assertion The change in internal energy and change in heat enthalpy does not depend upon the path by which changes are brought in. Reason Both \( \Delta U \) and \( \Delta H \) are path independent as U and H are state functions.
• Liquid benzene burns in oxygen according to: \( 2 C_{6} H_{6}+15 O_{2} \rightarrow 12 C O_{2}+6 H_{2} O \) If density of liquid benzene is \( 0.88 \mathrm{g} / \mathrm{cc} \) what volume of \( \boldsymbol{O}_{2} \) at \( \mathrm{STP} \) is needed to complete the combustion of 39 cc of liquid benzene?
• When a bomb calorimeter is used to determine the heat of reaction, which property of the system under investigation is most likely to remain constant?
• When heat is given to gas in an isothermal change, the result will be

⚔️ Practice NEET Chemistry free + battle 1v1 →