Change in volume from 1 mole of graphite to 1 mole of diamond. ΔV = 12/3.31 − 12/2.25 = −1.71 cm³. Gibb's free energy is the measure of useful work done at constant temperature and pressure. ΔG = −PΔV.

Question

Accepted Answer

ΔG = −1895 J. The formula ΔG = −PΔV is used, where ΔV = −1.71 cm³ = −1.71 × 10⁻⁶ m³. Assuming standard pressure P = 1 atm = 101325 Pa, ΔG = −101325 × (−1.71 × 10⁻⁶) = −1895 J.

Change in volume from 1 mole of graphite to 1 mole of diamond. ΔV = 12/3.31 − 12/2.25 = −1.71 cm³. Gibb's free energy is the measure of useful work done at constant temperature and pressure. ΔG = −PΔV.

Solution

Related NEET Chemistry questions