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ΔH = ΔE + ΔnRT Δn = 3 − (1 + 3) = 3 − 6 = −3 ΔH = ΔE − (−3RT)

1. (a) ΔH = ΔE − 3RT
2. (b) ΔH = ΔE + 3RT
3. (c) ΔH = ΔE + ΔnRT
4. (d) ΔH = ΔE − ΔnRT

Correct answer: (b) ΔH = ΔE + 3RT

Solution

The calculation shows that Δn = -3, and substituting this into the equation gives ΔH = ΔE - (-3RT), which simplifies to ΔH = ΔE + 3RT.

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