Exams › NEET › Chemistry

W = −PΔV = −6 litre atmosphere. Calculate the work done.

1. W = −6 × 101.32 = −608 J
2. W = −6 × 100 = −600 J
3. W = −6 × 101.32 = −608 kJ
4. W = −6 × 100 = −600 kJ

Correct answer: W = −6 × 101.32 = −608 J

Solution

Work in chemistry is often reported in joules, so the given value in litre-atmosphere must be converted. Since 1 L·atm = 101.32 J, −6 L·atm becomes about −608 J.

Related NEET Chemistry questions

• An ideal gas is compressed in a closed container its U?
• Internal energy does not include
• Assertion The change in internal energy and change in heat enthalpy does not depend upon the path by which changes are brought in. Reason Both \( \Delta U \) and \( \Delta H \) are path independent as U and H are state functions.
• Liquid benzene burns in oxygen according to: \( 2 C_{6} H_{6}+15 O_{2} \rightarrow 12 C O_{2}+6 H_{2} O \) If density of liquid benzene is \( 0.88 \mathrm{g} / \mathrm{cc} \) what volume of \( \boldsymbol{O}_{2} \) at \( \mathrm{STP} \) is needed to complete the combustion of 39 cc of liquid benzene?
• When a bomb calorimeter is used to determine the heat of reaction, which property of the system under investigation is most likely to remain constant?
• When heat is given to gas in an isothermal change, the result will be

⚔️ Practice NEET Chemistry free + battle 1v1 →