Exams › NEET › Chemistry

Given Cp = 75 JK⁻¹ mol⁻¹, n = 100/18 mole, Q = 1000 J. Calculate ΔT.

1. ΔT = 1000 × 18 / 100 × 75 = 2.4 K
2. ΔT = 1000 × 18 / 100 × 75 = 2.5 K
3. ΔT = 1000 × 18 / 100 × 75 = 2.3 K
4. ΔT = 1000 × 18 / 100 × 75 = 2.6 K

Correct answer: ΔT = 1000 × 18 / 100 × 75 = 2.4 K

Solution

The formula for heat transfer is Q = n × Cp × ΔT. Rearranging for ΔT gives ΔT = Q / (n × Cp). Substituting the values: ΔT = 1000 / [(100/18) × 75] = 2.4 K.

Related NEET Chemistry questions

• An ideal gas is compressed in a closed container its U?
• Internal energy does not include
• Assertion The change in internal energy and change in heat enthalpy does not depend upon the path by which changes are brought in. Reason Both \( \Delta U \) and \( \Delta H \) are path independent as U and H are state functions.
• Liquid benzene burns in oxygen according to: \( 2 C_{6} H_{6}+15 O_{2} \rightarrow 12 C O_{2}+6 H_{2} O \) If density of liquid benzene is \( 0.88 \mathrm{g} / \mathrm{cc} \) what volume of \( \boldsymbol{O}_{2} \) at \( \mathrm{STP} \) is needed to complete the combustion of 39 cc of liquid benzene?
• When a bomb calorimeter is used to determine the heat of reaction, which property of the system under investigation is most likely to remain constant?
• When heat is given to gas in an isothermal change, the result will be

⚔️ Practice NEET Chemistry free + battle 1v1 →