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As MgO is an oxide of weak base, hence some energy is lost to break MgO (s). Hence enthalpy is less than −57.33 kJ mol⁻¹.

1. ΔH = −57.33 kJ mol⁻¹
2. ΔH = −58.00 kJ mol⁻¹
3. ΔH = −56.00 kJ mol⁻¹
4. ΔH = −57.00 kJ mol⁻¹

Correct answer: ΔH = −56.00 kJ mol⁻¹

Solution

The question states that the enthalpy is less than −57.33 kJ mol⁻¹ due to energy loss in breaking MgO. Among the options, −56.00 kJ mol⁻¹ is the only value less than −57.33 kJ mol⁻¹.

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