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Given 4H(g) → 2H2(g); ΔH = −869.6 kJ or 2H2(g) → 4H(g); ΔH = 869.6 kJ. H2(g) → 2H(g); ΔH = 434.8 kJ. Calculate ΔH.

1. (a) ΔH = −869.6 kJ
2. (b) ΔH = 869.6 kJ
3. (c) ΔH = 434.8 kJ
4. (d) ΔH = −434.8 kJ

Correct answer: (c) ΔH = 434.8 kJ

Solution

The reaction H2(g) → 2H(g) directly corresponds to the given enthalpy change ΔH = 434.8 kJ, as stated in the question. No further calculation is needed.

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