Exams › NEET › Chemistry

For adiabatic process ΔQ = 0. In free expansion, external pressure is zero. Thus, work done W = 0 and ΔE = W = 0. If ΔE = 0, then ΔT = ?

1. (a) ΔT = 0
2. (b) ΔT > 0
3. (c) ΔT < 0
4. (d) ΔT = constant

Correct answer: (a) ΔT = 0

Solution

In a free expansion, no work is done (W = 0), and since the process is adiabatic (ΔQ = 0), the internal energy change (ΔE) is also zero. For an ideal gas, ΔE is directly proportional to ΔT, so ΔT = 0.

Related NEET Chemistry questions

• An ideal gas is compressed in a closed container its U?
• Internal energy does not include
• Assertion The change in internal energy and change in heat enthalpy does not depend upon the path by which changes are brought in. Reason Both \( \Delta U \) and \( \Delta H \) are path independent as U and H are state functions.
• Liquid benzene burns in oxygen according to: \( 2 C_{6} H_{6}+15 O_{2} \rightarrow 12 C O_{2}+6 H_{2} O \) If density of liquid benzene is \( 0.88 \mathrm{g} / \mathrm{cc} \) what volume of \( \boldsymbol{O}_{2} \) at \( \mathrm{STP} \) is needed to complete the combustion of 39 cc of liquid benzene?
• When a bomb calorimeter is used to determine the heat of reaction, which property of the system under investigation is most likely to remain constant?
• When heat is given to gas in an isothermal change, the result will be

⚔️ Practice NEET Chemistry free + battle 1v1 →