The enthalpy and entropy change for the reaction Br₂(l) + Cl₂(g) → 2 BrCl(g) are 30 kJ mol⁻¹ and 105 J K⁻¹ mol⁻¹ respectively. The temperature at which the reaction will be in equilibrium is:

Question

Accepted Answer

285.7 K. At equilibrium, ΔG = 0, so ΔH = TΔS. Substituting ΔH = 30 kJ mol⁻¹ = 30000 J mol⁻¹ and ΔS = 105 J K⁻¹ mol⁻¹, T = ΔH/ΔS = 30000/105 ≈ 285.7 K.

The enthalpy and entropy change for the reaction Br₂(l) + Cl₂(g) → 2 BrCl(g) are 30 kJ mol⁻¹ and 105 J K⁻¹ mol⁻¹ respectively. The temperature at which the reaction will be in equilibrium is:

Solution

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