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The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm⁻³, respectively. If the standard free energy difference (ΔG⁰) is equal to 1895 J mol⁻¹, the pressure at which graphite will be transformed into diamond at 298 K is

1. 9.92 × 10⁵ Pa
2. 9.92 × 10⁸ Pa
3. 9.92 × 10⁷ Pa
4. 9.92 × 10⁶ Pa

Correct answer: 9.92 × 10⁷ Pa

Solution

The pressure required for the transformation can be calculated using the relation ΔG = ΔV × P, where ΔV is the volume change. Using the densities of graphite and diamond, ΔV is calculated, and substituting ΔG⁰ = 1895 J mol⁻¹, the pressure is found to be 9.92 × 10⁷ Pa.

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