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The entropy change in the fusion of one mole of a solid melting at 27°C (Latent heat of fusion, 2930 J mol⁻¹) is:

1. 9.77 J K⁻¹ mol⁻¹
2. 10.73 J K⁻¹ mol⁻¹
3. 2930 J K⁻¹ mol⁻¹
4. 108.5 J K⁻¹ mol⁻¹

Correct answer: 9.77 J K⁻¹ mol⁻¹

Solution

The entropy change (ΔS) is calculated using the formula ΔS = ΔH/T, where ΔH is the latent heat of fusion and T is the temperature in Kelvin. Converting 27°C to Kelvin gives T = 300 K. Substituting the values, ΔS = 2930 J mol⁻¹ / 300 K = 9.77 J K⁻¹ mol⁻¹.

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